feat: 初始化画个标仓库 - AI驱动设计系统(BYOK模式) - 224源/371504图标+25海报源+130技能

2026-10-03 21:44:18 +08:00
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+/**
+ * 画个标 · 留学主题字体库
+ * 包含中文/英文排版推荐 + 可选的 Google Fonts 网络加载
+ */
+const HGB_Fonts = {
+  groups: [
+    {
+      name: '中文 · 正式',
+      items: [
+        { family: 'SimSun', cn: '宋体', web: false, desc: '经典衬线，典雅学术' },
+        { family: 'SimHei', cn: '黑体', web: false, desc: '现代无衬线，稳重清晰' },
+        { family: 'KaiTi', cn: '楷体', web: false, desc: '手写感，亲和人文' },
+        { family: 'Microsoft YaHei', cn: '微软雅黑', web: false, desc: '屏幕友好，现代通用' }
+      ]
+    },
+    {
+      name: '英文 · 衬线',
+      items: [
+        { family: 'Georgia', cn: 'Georgia', web: false, desc: '经典衬线，传统名校' },
+        { family: 'Times New Roman', cn: 'Times', web: false, desc: '报刊气质，学术规范' },
+        { family: 'Playfair Display', cn: 'Playfair', web: true, desc: '高端时尚衬线（网络加载）' }
+      ]
+    },
+    {
+      name: '英文 · 无衬线',
+      items: [
+        { family: 'Arial', cn: 'Arial', web: false, desc: '清晰通用，商务首选' },
+        { family: 'Verdana', cn: 'Verdana', web: false, desc: '宽字距，易读性强' },
+        { family: 'Montserrat', cn: 'Montserrat', web: true, desc: '现代几何感（网络加载）' },
+        { family: 'Poppins', cn: 'Poppins', web: true, desc: '圆润时尚（网络加载）' }
+      ]
+    },
+    {
+      name: '英文 · 装饰',
+      items: [
+        { family: 'Impact', cn: 'Impact', web: false, desc: '粗壮有力，标题冲击' },
+        { family: 'Courier New', cn: 'Courier', web: false, desc: '等宽打字机，复古文艺' }
+      ]
+    }
+  ]
+};
+
+/** 动态加载 Google Fonts（网络可用时） */
+HGB_Fonts.loadWebFont = function (family) {
+  const id = 'hgb-font-' + family.replace(/[^a-zA-Z0-9]/g, '');
+  if (document.getElementById(id)) return;
+  const link = document.createElement('link');
+  link.id = id;
+  link.rel = 'stylesheet';
+  link.href = 'https://fonts.googleapis.com/css2?family=' +
+    encodeURIComponent(family.replace(/ /g, '+')) + ':wght@400;700;900&display=swap';
+  document.head.appendChild(link);
+};
+
+/** 按 family 查找字体项 */
+HGB_Fonts.find = function (family) {
+  for (const g of this.groups) {
+    const f = g.items.find(i => i.family === family);
+    if (f) return f;
+  }
+  return null;
+};